-9.8t^2=-11

Solution for -9.8t^2=-11 equation:

-9.8t^2=-11

We move all terms to the left:

-9.8t^2-(-11)=0

We add all the numbers together, and all the variables

-9.8t^2+11=0

a = -9.8; b = 0; c = +11;
Δ = b2-4ac
Δ = 02-4·(-9.8)·11
Δ = 431.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{431.2}}{2*-9.8}=\frac{0-\sqrt{431.2}}{-19.6}
=-\frac{\sqrt{}}{-19.6}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{431.2}}{2*-9.8}=\frac{0+\sqrt{431.2}}{-19.6}
=\frac{\sqrt{}}{-19.6}
$